Distance from Alexandria, Tennessee to Seymour, Indiana

Wondering how far is Seymour, Indiana from Alexandria, Tennessee? Here's our driving distance calculation from Alexandria to Seymour.

Distance
239 mi
385 km
Travel Time
3 hr 58 min

The driving distance between Alexandria, Tennessee and Seymour, Indiana is 239 mi or 385 km . It takes 3 hr 58 min to reach Seymour from Alexandria by road. The distance by air route is 199 mi / 320 km.

There are 3 routes to reach Seymour, Indiana from Alexandria, Tennessee.

Via I-65 N
239 mi / 385 km - 3 hr 58 min
Via US-31E N and I-65 N
233 mi / 375 km - 4 hr 2 min
Via US-31E N, KY-101 N and I-65 N
234 mi / 377 km - 3 hr 58 min

Alexandria, Tennessee

Time 03:09:52
Latitude 36.0775587
Longitude -86.0333222
State Tennessee
Zip 37012
Timezone America/Kentucky/Monticello

Seymour, Indiana

Time 03:09:52
Latitude 38.9592201
Longitude -85.8902547
State Indiana
Zip 47274
Timezone America/Indiana/Vevay

Nearby Cities

Flat Top Mountain

84 mi / 135 km

Mowbray Mountain

85 mi / 137 km

Fairmount

90 mi / 145 km

Spring City

101 mi / 163 km

Walden

92 mi / 148 km

Rockwood

97 mi / 156 km

Soddy-Daisy

94 mi / 151 km

Sale Creek

94 mi / 151 km

Sunbright

94 mi / 151 km

Signal Mountain

95 mi / 153 km

Alexandria Distance to Popular Cities

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