Distance from Alexandria Bay, New York to Marlow, Oklahoma

Wondering how far is Marlow, Oklahoma from Alexandria Bay, New York? Here's our driving distance calculation from Alexandria Bay to Marlow.

Distance
1543 mi
2483 km
Travel Time
22 hr 35 min

The driving distance between Alexandria Bay, New York and Marlow, Oklahoma is 1543 mi or 2483 km . It takes 22 hr 35 min to reach Marlow from Alexandria Bay by road. The distance by air route is 1346 mi / 2166 km.

There are 3 routes to reach Marlow, Oklahoma from Alexandria Bay, New York.

Via I-70 W
1543 mi / 2483 km - 22 hr 35 min
Via I-44 W
1546 mi / 2488 km - 22 hr 41 min
Via I-90 W and I-44 W
1592 mi / 2562 km - 23 hr 17 min

Alexandria Bay, New York

Time 11:54:56
Latitude 44.3358836
Longitude -75.9177309
State New York
Zip
Timezone America/New_York

Marlow, Oklahoma

Time 09:54:56
Latitude 34.6481318
Longitude -97.9580933
State Oklahoma
Zip 73055
Timezone America/Denver

Nearby Cities

Village Green

105 mi / 169 km

Jordan

113 mi / 182 km

Weedsport

117 mi / 188 km

Port Byron

121 mi / 195 km

Cayuga

133 mi / 214 km

Clyde

141 mi / 227 km

Sharon Springs

150 mi / 241 km

Fultonville

154 mi / 248 km

Fonda

155 mi / 249 km

Tribes Hill

159 mi / 256 km

Alexandria Bay Distance to Popular Cities

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