Distance from Alexandria Bay, New York to Montrose-Ghent, Ohio
Wondering how far is Montrose-Ghent, Ohio from Alexandria Bay, New York? Here's our driving distance calculation from Alexandria Bay to Montrose-Ghent.
The driving distance between Alexandria Bay, New York and Montrose-Ghent, Ohio is 447 mi or 719 km . It takes 6 hr 37 min to reach Montrose-Ghent from Alexandria Bay by road. The distance by air route is 365 mi / 587 km.
There are 3 routes to reach Montrose-Ghent, Ohio from Alexandria Bay, New York.
447 mi / 719 km - 6 hr 37 min
479 mi / 771 km - 7 hr 5 min
482 mi / 776 km - 7 hr 21 min
Alexandria Bay, New York
Time | 08:14:30 |
Latitude | 44.3358836 |
Longitude | -75.9177309 |
State | New York |
Zip | |
Timezone | America/New_York |
Montrose-Ghent, Ohio
Time | 08:14:30 |
Latitude | 41.1537022 |
Longitude | -81.6528219 |
State | Ohio |
Zip | |
Timezone | America/Detroit |
Nearby Cities
Village Green
105 mi / 169 km
Jordan
113 mi / 182 km
Weedsport
117 mi / 188 km
Port Byron
121 mi / 195 km
Cayuga
133 mi / 214 km
Clyde
141 mi / 227 km
Sharon Springs
150 mi / 241 km
Fultonville
154 mi / 248 km
Fonda
155 mi / 249 km
Tribes Hill
159 mi / 256 km
Alexandria Bay Distance to Popular Cities
Route | Distance |
---|---|
Alexandria Bay to Village Green | 105 mi / 169 km |
Alexandria Bay to Jordan | 113 mi / 182 km |
Alexandria Bay to Weedsport | 117 mi / 188 km |
Alexandria Bay to Port Byron | 121 mi / 195 km |
Alexandria Bay to Cayuga | 133 mi / 214 km |
Alexandria Bay to Clyde | 141 mi / 227 km |
Alexandria Bay to Sharon Springs | 150 mi / 241 km |
Alexandria Bay to Fultonville | 154 mi / 248 km |
Alexandria Bay to Fonda | 155 mi / 249 km |
Alexandria Bay to Tribes Hill | 159 mi / 256 km |
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