Distance from Alexandria Bay, New York to San Angelo, Texas

Wondering how far is San Angelo, Texas from Alexandria Bay, New York? Here's our driving distance calculation from Alexandria Bay to San Angelo.

Distance
1847 mi
2972 km
Travel Time
27 hr

The driving distance between Alexandria Bay, New York and San Angelo, Texas is 1847 mi or 2972 km . It takes 27 hr to reach San Angelo from Alexandria Bay by road. The distance by air route is 1596 mi / 2569 km.

There are 3 routes to reach San Angelo, Texas from Alexandria Bay, New York.

Via I-70 W
1847 mi / 2972 km - 27 hr
Via I-30 W
1859 mi / 2992 km - 27 hr
Via I-44 W
1849 mi / 2976 km - 27 hr

Alexandria Bay, New York

Time 09:23:14
Latitude 44.3358836
Longitude -75.9177309
State New York
Zip
Timezone America/New_York

San Angelo, Texas

Time 07:23:14
Latitude 31.4637723
Longitude -100.4370375
State Texas
Zip
Timezone America/Denver

Nearby Cities

Village Green

105 mi / 169 km

Jordan

113 mi / 182 km

Weedsport

117 mi / 188 km

Port Byron

121 mi / 195 km

Cayuga

133 mi / 214 km

Clyde

141 mi / 227 km

Sharon Springs

150 mi / 241 km

Fultonville

154 mi / 248 km

Fonda

155 mi / 249 km

Tribes Hill

159 mi / 256 km

Alexandria Bay Distance to Popular Cities

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