Distance from Alexandria Bay, New York to Sanford, Alabama

Wondering how far is Sanford, Alabama from Alexandria Bay, New York? Here's our driving distance calculation from Alexandria Bay to Sanford.

Distance
1316 mi
2118 km
Travel Time
19 hr 15 min

The driving distance between Alexandria Bay, New York and Sanford, Alabama is 1316 mi or 2118 km . It takes 19 hr 15 min to reach Sanford from Alexandria Bay by road. The distance by air route is 1065 mi / 1714 km.

There are 3 routes to reach Sanford, Alabama from Alexandria Bay, New York.

Via I-65 S
1316 mi / 2118 km - 19 hr 15 min
Via I-81 S
1323 mi / 2129 km - 19 hr 29 min
Via I-81 S and I-85 S
1359 mi / 2187 km - 20 hr 19 min

Alexandria Bay, New York

Time 11:55:17
Latitude 44.3358836
Longitude -75.9177309
State New York
Zip
Timezone America/New_York

Sanford, Alabama

Time 11:55:17
Latitude 31.2982254
Longitude -86.3891217
State Alabama
Zip
Timezone America/Kentucky/Monticello

Nearby Cities

Village Green

105 mi / 169 km

Jordan

113 mi / 182 km

Weedsport

117 mi / 188 km

Port Byron

121 mi / 195 km

Cayuga

133 mi / 214 km

Clyde

141 mi / 227 km

Sharon Springs

150 mi / 241 km

Fultonville

154 mi / 248 km

Fonda

155 mi / 249 km

Tribes Hill

159 mi / 256 km

Alexandria Bay Distance to Popular Cities

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