Distance from Alexandria Bay, New York to Sibley, Illinois

Wondering how far is Sibley, Illinois from Alexandria Bay, New York? Here's our driving distance calculation from Alexandria Bay to Sibley.

Distance
790 mi
1271 km
Travel Time
11 hr 47 min

The driving distance between Alexandria Bay, New York and Sibley, Illinois is 790 mi or 1271 km . It takes 11 hr 47 min to reach Sibley from Alexandria Bay by road. The distance by air route is 685 mi / 1102 km.

There are 3 routes to reach Sibley, Illinois from Alexandria Bay, New York.

Via ON-401 W
790 mi / 1271 km - 11 hr 47 min
Via I-90 W
849 mi / 1366 km - 12 hr 39 min
Via I-90 W and US-30 W
842 mi / 1355 km - 13 hr 3 min

Alexandria Bay, New York

Time 11:53:15
Latitude 44.3358836
Longitude -75.9177309
State New York
Zip
Timezone America/New_York

Sibley, Illinois

Time 10:53:15
Latitude 40.5869788
Longitude -88.3811647
State Illinois
Zip 61773
Timezone America/Chicago

Nearby Cities

Village Green

105 mi / 169 km

Jordan

113 mi / 182 km

Weedsport

117 mi / 188 km

Port Byron

121 mi / 195 km

Cayuga

133 mi / 214 km

Clyde

141 mi / 227 km

Sharon Springs

150 mi / 241 km

Fultonville

154 mi / 248 km

Fonda

155 mi / 249 km

Tribes Hill

159 mi / 256 km

Alexandria Bay Distance to Popular Cities

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