Distance from Alexandria Bay, New York to Sioux City, Iowa

Wondering how far is Sioux City, Iowa from Alexandria Bay, New York? Here's our driving distance calculation from Alexandria Bay to Sioux City.

Distance
1204 mi
1938 km
Travel Time
18 hr

The driving distance between Alexandria Bay, New York and Sioux City, Iowa is 1204 mi or 1938 km . It takes 18 hr to reach Sioux City from Alexandria Bay by road. The distance by air route is 1033 mi / 1662 km.

There are 3 routes to reach Sioux City, Iowa from Alexandria Bay, New York.

Via ON-401 W
1204 mi / 1938 km - 18 hr
Via ON-401 W and US-20 W
1205 mi / 1939 km - 18 hr 1 min
Via I-90 W
1263 mi / 2033 km - 18 hr 52 min

Alexandria Bay, New York

Time 10:05:54
Latitude 44.3358836
Longitude -75.9177309
State New York
Zip
Timezone America/New_York

Sioux City, Iowa

Time 09:05:54
Latitude 42.4963416
Longitude -96.4049408
State Iowa
Zip
Timezone America/North_Dakota/New_Salem

Nearby Cities

Village Green

105 mi / 169 km

Jordan

113 mi / 182 km

Weedsport

117 mi / 188 km

Port Byron

121 mi / 195 km

Cayuga

133 mi / 214 km

Clyde

141 mi / 227 km

Sharon Springs

150 mi / 241 km

Fultonville

154 mi / 248 km

Fonda

155 mi / 249 km

Tribes Hill

159 mi / 256 km

Alexandria Bay Distance to Popular Cities

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