Distance from Alexandria Bay, New York to Summerlin South, Nevada

Wondering how far is Summerlin South, Nevada from Alexandria Bay, New York? Here's our driving distance calculation from Alexandria Bay to Summerlin South.

Distance
2460 mi
3959 km
Travel Time
36 hr

The driving distance between Alexandria Bay, New York and Summerlin South, Nevada is 2460 mi or 3959 km . It takes 36 hr to reach Summerlin South from Alexandria Bay by road. The distance by air route is 2132 mi / 3431 km.

There are 3 routes to reach Summerlin South, Nevada from Alexandria Bay, New York.

Via I-80 W
2460 mi / 3959 km - 36 hr
Via I-90 W and I-80 W
2518 mi / 4052 km - 37 hr
Via I-70 W
2583 mi / 4157 km - 37 hr

Alexandria Bay, New York

Time 09:20:05
Latitude 44.3358836
Longitude -75.9177309
State New York
Zip
Timezone America/New_York

Summerlin South, Nevada

Time 06:20:05
Latitude 36.1349048
Longitude -115.3280016
State Nevada
Zip
Timezone America/Los_Angeles

Nearby Cities

Village Green

105 mi / 169 km

Jordan

113 mi / 182 km

Weedsport

117 mi / 188 km

Port Byron

121 mi / 195 km

Cayuga

133 mi / 214 km

Clyde

141 mi / 227 km

Sharon Springs

150 mi / 241 km

Fultonville

154 mi / 248 km

Fonda

155 mi / 249 km

Tribes Hill

159 mi / 256 km

Alexandria Bay Distance to Popular Cities

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