Distance from Alexandria, Alabama to Jefferson Heights, New York
Wondering how far is Jefferson Heights, New York from Alexandria, Alabama? Here's our driving distance calculation from Alexandria to Jefferson Heights.
The driving distance between Alexandria, Alabama and Jefferson Heights, New York is 1018 mi or 1638 km . It takes 15 hr 12 min to reach Jefferson Heights from Alexandria by road. The distance by air route is 875 mi / 1408 km.
There are 3 routes to reach Jefferson Heights, New York from Alexandria, Alabama.
1018 mi / 1638 km - 15 hr 12 min
1038 mi / 1670 km - 15 hr 34 min
1073 mi / 1727 km - 16 hr 6 min
Alexandria, Alabama
| Time | 23:22:32 |
| Latitude | 33.7739892 |
| Longitude | -85.885523 |
| State | Alabama |
| Zip | |
| Timezone | America/Kentucky/Monticello |
Jefferson Heights, New York
| Time | 23:22:32 |
| Latitude | 42.2339766 |
| Longitude | -73.8823515 |
| State | New York |
| Zip | |
| Timezone | America/New_York |
Alexandria Distance to Popular Cities
| Route | Distance |
|---|---|
| Alexandria to Waco | 52 mi / 84 km |
| Alexandria to Bowdon | 52 mi / 84 km |
| Alexandria to Lindale | 58 mi / 93 km |
| Alexandria to Rockmart | 60 mi / 97 km |
| Alexandria to Rome | 62 mi / 100 km |
| Alexandria to Aragon | 62 mi / 100 km |
| Alexandria to Villa Rica | 68 mi / 109 km |
| Alexandria to Shannon | 70 mi / 113 km |
| Alexandria to Franklin | 71 mi / 114 km |
| Alexandria to Euharlee | 74 mi / 119 km |
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