Distance from Ashland Heights, South Dakota to Boynton Beach, Florida

Wondering how far is Boynton Beach, Florida from Ashland Heights, South Dakota? Here's our driving distance calculation from Ashland Heights to Boynton Beach.

Distance
2107 mi
3391 km
Travel Time
30 hr

The driving distance between Ashland Heights, South Dakota and Boynton Beach, Florida is 2107 mi or 3391 km . It takes 30 hr to reach Boynton Beach from Ashland Heights by road. The distance by air route is 1767 mi / 2844 km.

There are 3 routes to reach Boynton Beach, Florida from Ashland Heights, South Dakota.

Via I-75 S
2107 mi / 3391 km - 30 hr
Via I-29 S and I-75 S
2139 mi / 3442 km - 31 hr
Via I-90 E
2233 mi / 3594 km - 32 hr

Ashland Heights, South Dakota

Time 07:30:19
Latitude 44.1297097
Longitude -103.1251785
State South Dakota
Zip
Timezone America/North_Dakota/New_Salem

Boynton Beach, Florida

Time 08:30:19
Latitude 26.5317866
Longitude -80.0905465
State Florida
Zip
Timezone America/Kentucky/Monticello

Nearby Cities

Norris

130 mi / 209 km

Murdo

130 mi / 209 km

Draper

140 mi / 225 km

White River

154 mi / 248 km

Parmelee

149 mi / 240 km

Vivian

153 mi / 246 km

Soldier Creek

159 mi / 256 km

Lance Creek

161 mi / 259 km

Rosebud

161 mi / 259 km

Two Strike

162 mi / 261 km

Ashland Heights Distance to Popular Cities

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