Distance from Ashland Heights, South Dakota to Deerfield Beach, Florida

Wondering how far is Deerfield Beach, Florida from Ashland Heights, South Dakota? Here's our driving distance calculation from Ashland Heights to Deerfield Beach.

Distance
2123 mi
3417 km
Travel Time
30 hr

The driving distance between Ashland Heights, South Dakota and Deerfield Beach, Florida is 2123 mi or 3417 km . It takes 30 hr to reach Deerfield Beach from Ashland Heights by road. The distance by air route is 1778 mi / 2861 km.

There are 3 routes to reach Deerfield Beach, Florida from Ashland Heights, South Dakota.

Via I-75 S
2123 mi / 3417 km - 30 hr
Via I-29 S and I-75 S
2155 mi / 3468 km - 31 hr
Via I-90 E
2249 mi / 3619 km - 32 hr

Ashland Heights, South Dakota

Time 15:37:46
Latitude 44.1297097
Longitude -103.1251785
State South Dakota
Zip
Timezone America/North_Dakota/New_Salem

Deerfield Beach, Florida

Time 16:37:46
Latitude 26.3184123
Longitude -80.0997657
State Florida
Zip
Timezone America/Kentucky/Monticello

Nearby Cities

Norris

130 mi / 209 km

Murdo

130 mi / 209 km

Draper

140 mi / 225 km

White River

154 mi / 248 km

Parmelee

149 mi / 240 km

Vivian

153 mi / 246 km

Soldier Creek

159 mi / 256 km

Lance Creek

161 mi / 259 km

Rosebud

161 mi / 259 km

Two Strike

162 mi / 261 km

Ashland Heights Distance to Popular Cities

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