Distance from Ashland Heights, South Dakota to Jacksonville, Texas

Wondering how far is Jacksonville, Texas from Ashland Heights, South Dakota? Here's our driving distance calculation from Ashland Heights to Jacksonville.

Distance
1176 mi
1893 km
Travel Time
17 hr 23 min

The driving distance between Ashland Heights, South Dakota and Jacksonville, Texas is 1176 mi or 1893 km . It takes 17 hr 23 min to reach Jacksonville from Ashland Heights by road. The distance by air route is 942 mi / 1516 km.

There are 3 routes to reach Jacksonville, Texas from Ashland Heights, South Dakota.

Via I-35 S
1176 mi / 1893 km - 17 hr 23 min
Via Heartland Expy and I-35 S
1206 mi / 1941 km - 17 hr 50 min
Via NE-2 E
1183 mi / 1904 km - 17 hr 54 min

Ashland Heights, South Dakota

Time 02:38:52
Latitude 44.1297097
Longitude -103.1251785
State South Dakota
Zip
Timezone America/North_Dakota/New_Salem

Jacksonville, Texas

Time 02:38:52
Latitude 31.963778
Longitude -95.2705042
State Texas
Zip 75766
Timezone America/Indiana/Tell_City

Nearby Cities

Norris

130 mi / 209 km

Murdo

130 mi / 209 km

Draper

140 mi / 225 km

White River

154 mi / 248 km

Parmelee

149 mi / 240 km

Vivian

153 mi / 246 km

Soldier Creek

159 mi / 256 km

Lance Creek

161 mi / 259 km

Rosebud

161 mi / 259 km

Two Strike

162 mi / 261 km

Ashland Heights Distance to Popular Cities

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