Distance from Ashland Heights, South Dakota to Jefferson Heights, New York

Wondering how far is Jefferson Heights, New York from Ashland Heights, South Dakota? Here's our driving distance calculation from Ashland Heights to Jefferson Heights.

Distance
1754 mi
2823 km
Travel Time
25 hr

The driving distance between Ashland Heights, South Dakota and Jefferson Heights, New York is 1754 mi or 2823 km . It takes 25 hr to reach Jefferson Heights from Ashland Heights by road. The distance by air route is 1471 mi / 2367 km.

There are 3 routes to reach Jefferson Heights, New York from Ashland Heights, South Dakota.

Via I-90 E
1754 mi / 2823 km - 25 hr
Via US-20 E and I-90 E
1764 mi / 2839 km - 27 hr
Via I-90 E and I-87 S
1748 mi / 2813 km - 25 hr

Ashland Heights, South Dakota

Time 09:00:42
Latitude 44.1297097
Longitude -103.1251785
State South Dakota
Zip
Timezone America/North_Dakota/New_Salem

Jefferson Heights, New York

Time 10:00:42
Latitude 42.2339766
Longitude -73.8823515
State New York
Zip
Timezone America/New_York

Nearby Cities

Norris

130 mi / 209 km

Murdo

130 mi / 209 km

Draper

140 mi / 225 km

White River

154 mi / 248 km

Parmelee

149 mi / 240 km

Vivian

153 mi / 246 km

Soldier Creek

159 mi / 256 km

Lance Creek

161 mi / 259 km

Rosebud

161 mi / 259 km

Two Strike

162 mi / 261 km

Ashland Heights Distance to Popular Cities

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