Distance from Ashland Heights, South Dakota to Petersburg, Virginia

Wondering how far is Petersburg, Virginia from Ashland Heights, South Dakota? Here's our driving distance calculation from Ashland Heights to Petersburg.

Distance
1731 mi
2786 km
Travel Time
25 hr

The driving distance between Ashland Heights, South Dakota and Petersburg, Virginia is 1731 mi or 2786 km . It takes 25 hr to reach Petersburg from Ashland Heights by road. The distance by air route is 1423 mi / 2290 km.

There are 3 routes to reach Petersburg, Virginia from Ashland Heights, South Dakota.

Via I-90 E
1731 mi / 2786 km - 25 hr
Via I-90 E and I-74
1725 mi / 2776 km - 25 hr
Via I-90 E and I-64 E
1735 mi / 2792 km - 25 hr

Ashland Heights, South Dakota

Time 02:27:48
Latitude 44.1297097
Longitude -103.1251785
State South Dakota
Zip
Timezone America/North_Dakota/New_Salem

Petersburg, Virginia

Time 03:27:48
Latitude 37.2279279
Longitude -77.4019267
State Virginia
Zip
Timezone America/New_York

Nearby Cities

Norris

130 mi / 209 km

Murdo

130 mi / 209 km

Draper

140 mi / 225 km

White River

154 mi / 248 km

Parmelee

149 mi / 240 km

Vivian

153 mi / 246 km

Soldier Creek

159 mi / 256 km

Lance Creek

161 mi / 259 km

Rosebud

161 mi / 259 km

Two Strike

162 mi / 261 km

Ashland Heights Distance to Popular Cities

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