Distance from Ashland Heights, South Dakota to Seymour, Tennessee

Wondering how far is Seymour, Tennessee from Ashland Heights, South Dakota? Here's our driving distance calculation from Ashland Heights to Seymour.

Distance
1442 mi
2321 km
Travel Time
20 hr 44 min

The driving distance between Ashland Heights, South Dakota and Seymour, Tennessee is 1442 mi or 2321 km . It takes 20 hr 44 min to reach Seymour from Ashland Heights by road. The distance by air route is 1168 mi / 1880 km.

There are 3 routes to reach Seymour, Tennessee from Ashland Heights, South Dakota.

Via I-29 S
1442 mi / 2321 km - 20 hr 44 min
Via I-90 E
1457 mi / 2345 km - 20 hr 58 min
Via I-90 E and I-74
1443 mi / 2322 km - 20 hr 52 min

Ashland Heights, South Dakota

Time 08:28:04
Latitude 44.1297097
Longitude -103.1251785
State South Dakota
Zip
Timezone America/North_Dakota/New_Salem

Seymour, Tennessee

Time 09:28:04
Latitude 35.8725599
Longitude -83.7740198
State Tennessee
Zip
Timezone America/Kentucky/Monticello

Nearby Cities

Norris

130 mi / 209 km

Murdo

130 mi / 209 km

Draper

140 mi / 225 km

White River

154 mi / 248 km

Parmelee

149 mi / 240 km

Vivian

153 mi / 246 km

Soldier Creek

159 mi / 256 km

Lance Creek

161 mi / 259 km

Rosebud

161 mi / 259 km

Two Strike

162 mi / 261 km

Ashland Heights Distance to Popular Cities

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