Distance from Chapmanville, West Virginia to Saunders Lake, Oregon

Wondering how far is Saunders Lake, Oregon from Chapmanville, West Virginia? Here's our driving distance calculation from Chapmanville to Saunders Lake.

Distance
2666 mi
4291 km
Travel Time
40 hr

The driving distance between Chapmanville, West Virginia and Saunders Lake, Oregon is 2666 mi or 4291 km . It takes 40 hr to reach Saunders Lake from Chapmanville by road. The distance by air route is 2217 mi / 3568 km.

There are 2 routes to reach Saunders Lake, Oregon from Chapmanville, West Virginia.

Via I-80 W
2666 mi / 4291 km - 40 hr
Via I-80 W and I-84 W
2669 mi / 4295 km - 40 hr

Chapmanville, West Virginia

Time 09:36:25
Latitude 37.9737114
Longitude -82.0173502
State West Virginia
Zip 25508
Timezone America/Indiana/Vevay

Saunders Lake, Oregon

Time 07:36:25
Latitude 43.5248362
Longitude -124.2165041
State Oregon
Zip 97459
Timezone America/Boise

Nearby Cities

Bristol

177 mi / 285 km

Bristol

177 mi / 285 km

Wetherington

215 mi / 346 km

Wright-Patterson AFB

239 mi / 385 km

Russell Springs

237 mi / 381 km

Forest Hills

239 mi / 385 km

Lake Mohawk

242 mi / 389 km

Bermuda Run

259 mi / 417 km

Ten Broeck

244 mi / 393 km

Thornhill

245 mi / 394 km

Chapmanville Distance to Popular Cities

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