Distance from Chappaqua, New York to Gainesville, Florida

Wondering how far is Gainesville, Florida from Chappaqua, New York? Here's our driving distance calculation from Chappaqua to Gainesville.

Distance
1095 mi
1762 km
Travel Time
16 hr 20 min

The driving distance between Chappaqua, New York and Gainesville, Florida is 1095 mi or 1762 km . It takes 16 hr 20 min to reach Gainesville from Chappaqua by road. The distance by air route is 929 mi / 1495 km.

There are 2 routes to reach Gainesville, Florida from Chappaqua, New York.

Via I-95 S
1095 mi / 1762 km - 16 hr 20 min
Via I-81 S
1132 mi / 1822 km - 16 hr 50 min

Chappaqua, New York

Time 08:30:55
Latitude 41.1595399
Longitude -73.764855
State New York
Zip
Timezone America/New_York

Gainesville, Florida

Time 08:30:55
Latitude 29.6519563
Longitude -82.324998
State Florida
Zip
Timezone America/Kentucky/Monticello

Nearby Cities

Peach Lake

23 mi / 37 km

West Point

28 mi / 45 km

Suffern

29 mi / 47 km

Leonia

31 mi / 50 km

Palisades Park

32 mi / 51 km

Hillburn

32 mi / 51 km

Sloatsburg

33 mi / 53 km

Ridgefield Park

34 mi / 55 km

Bogota

34 mi / 55 km

Oradell

35 mi / 56 km

Chappaqua Distance to Popular Cities

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