Distance from Chappaqua, New York to Gainesville, Texas

Wondering how far is Gainesville, Texas from Chappaqua, New York? Here's our driving distance calculation from Chappaqua to Gainesville.

Distance
1595 mi
2567 km
Travel Time
23 hr 43 min

The driving distance between Chappaqua, New York and Gainesville, Texas is 1595 mi or 2567 km . It takes 23 hr 43 min to reach Gainesville from Chappaqua by road. The distance by air route is 1379 mi / 2219 km.

There are 3 routes to reach Gainesville, Texas from Chappaqua, New York.

Via I-81 S
1595 mi / 2567 km - 23 hr 43 min
Via I-70 W
1634 mi / 2630 km - 24 hr
Via I-70 W and I-44 W
1619 mi / 2606 km - 24 hr

Chappaqua, New York

Time 08:22:16
Latitude 41.1595399
Longitude -73.764855
State New York
Zip
Timezone America/New_York

Gainesville, Texas

Time 06:22:16
Latitude 33.6259414
Longitude -97.1333453
State Texas
Zip 76240
Timezone America/Denver

Nearby Cities

Peach Lake

23 mi / 37 km

West Point

28 mi / 45 km

Suffern

29 mi / 47 km

Leonia

31 mi / 50 km

Palisades Park

32 mi / 51 km

Hillburn

32 mi / 51 km

Sloatsburg

33 mi / 53 km

Ridgefield Park

34 mi / 55 km

Bogota

34 mi / 55 km

Oradell

35 mi / 56 km

Chappaqua Distance to Popular Cities

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