Distance from Chappaqua, New York to Lexington, Oregon
Wondering how far is Lexington, Oregon from Chappaqua, New York? Here's our driving distance calculation from Chappaqua to Lexington.
The driving distance between Chappaqua, New York and Lexington, Oregon is 2772 mi or 4461 km . It takes 40 hr to reach Lexington from Chappaqua by road. The distance by air route is 2296 mi / 3695 km.
There are 2 routes to reach Lexington, Oregon from Chappaqua, New York.
2772 mi / 4461 km - 40 hr
2855 mi / 4595 km - 42 hr
Chappaqua, New York
Time | 02:04:30 |
Latitude | 41.1595399 |
Longitude | -73.764855 |
State | New York |
Zip | |
Timezone | America/New_York |
Lexington, Oregon
Time | 00:04:30 |
Latitude | 45.4451315 |
Longitude | -119.6844694 |
State | Oregon |
Zip | 97839 |
Timezone | America/Boise |
Nearby Cities
Peach Lake
23 mi / 37 km
West Point
28 mi / 45 km
Suffern
29 mi / 47 km
Leonia
31 mi / 50 km
Palisades Park
32 mi / 51 km
Hillburn
32 mi / 51 km
Sloatsburg
33 mi / 53 km
Ridgefield Park
34 mi / 55 km
Bogota
34 mi / 55 km
Oradell
35 mi / 56 km
Chappaqua Distance to Popular Cities
Route | Distance |
---|---|
Chappaqua to Peach Lake | 23 mi / 37 km |
Chappaqua to West Point | 28 mi / 45 km |
Chappaqua to Suffern | 29 mi / 47 km |
Chappaqua to Leonia | 31 mi / 50 km |
Chappaqua to Palisades Park | 32 mi / 51 km |
Chappaqua to Hillburn | 32 mi / 51 km |
Chappaqua to Sloatsburg | 33 mi / 53 km |
Chappaqua to Ridgefield Park | 34 mi / 55 km |
Chappaqua to Bogota | 34 mi / 55 km |
Chappaqua to Oradell | 35 mi / 56 km |
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