Distance from Dickeyville, Wisconsin to Summerlin South, Nevada

Wondering how far is Summerlin South, Nevada from Dickeyville, Wisconsin? Here's our driving distance calculation from Dickeyville to Summerlin South.

Distance
1636 mi
2633 km
Travel Time
23 hr 29 min

The driving distance between Dickeyville, Wisconsin and Summerlin South, Nevada is 1636 mi or 2633 km . It takes 23 hr 29 min to reach Summerlin South from Dickeyville by road. The distance by air route is 1389 mi / 2235 km.

There are 3 routes to reach Summerlin South, Nevada from Dickeyville, Wisconsin.

Via I-80 W and I-70 W
1636 mi / 2633 km - 23 hr 29 min
Via I-70 W
1763 mi / 2837 km - 25 hr
Via I-40 W
1874 mi / 3016 km - 27 hr

Dickeyville, Wisconsin

Time 03:12:57
Latitude 42.6272197
Longitude -90.5920723
State Wisconsin
Zip
Timezone America/Chicago

Summerlin South, Nevada

Time 01:12:57
Latitude 36.1349048
Longitude -115.3280016
State Nevada
Zip
Timezone America/Los_Angeles

Nearby Cities

Lake Summerset

77 mi / 124 km

Rock Island Arsenal

88 mi / 142 km

Candlewick Lake

105 mi / 169 km

Elgin

140 mi / 225 km

Rosemont

164 mi / 264 km

Golf

170 mi / 274 km

Justice

183 mi / 295 km

East Chicago

199 mi / 320 km

Olympia Fields

202 mi / 325 km

Cedar Lake

220 mi / 354 km

Dickeyville Distance to Popular Cities

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