Distance from Escatawpa, Mississippi to Lunenburg, Vermont

Wondering how far is Lunenburg, Vermont from Escatawpa, Mississippi? Here's our driving distance calculation from Escatawpa to Lunenburg.

Distance
1568 mi
2523 km
Travel Time
23 hr 25 min

The driving distance between Escatawpa, Mississippi and Lunenburg, Vermont is 1568 mi or 2523 km . It takes 23 hr 25 min to reach Lunenburg from Escatawpa by road. The distance by air route is 1332 mi / 2144 km.

There are 3 routes to reach Lunenburg, Vermont from Escatawpa, Mississippi.

Via I-85 N
1568 mi / 2523 km - 23 hr 25 min
Via I-81 N
1590 mi / 2559 km - 23 hr 35 min
Via I-85 N and I-81 N
1585 mi / 2551 km - 23 hr 43 min

Escatawpa, Mississippi

Time 05:56:17
Latitude 30.482056
Longitude -88.5503639
State Mississippi
Zip 39562
Timezone America/Kentucky/Monticello

Lunenburg, Vermont

Time 05:56:17
Latitude 44.4631136
Longitude -71.6820321
State Vermont
Zip
Timezone America/New_York

Nearby Cities

Tiger Point

113 mi / 182 km

Woodlawn Beach

116 mi / 187 km

Navarre

121 mi / 195 km

Hurlburt Field

134 mi / 216 km

Hester

159 mi / 256 km

Fort Novosel

216 mi / 348 km

Grand Isle

214 mi / 344 km

Tyndall AFB

234 mi / 377 km

Chattahoochee

246 mi / 396 km

Bristol

250 mi / 402 km

Escatawpa Distance to Popular Cities

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