Distance from Faribault, Minnesota to Sand Hill, Oklahoma

Wondering how far is Sand Hill, Oklahoma from Faribault, Minnesota? Here's our driving distance calculation from Faribault to Sand Hill.

Distance
678 mi
1091 km
Travel Time
10 hr 5 min

The driving distance between Faribault, Minnesota and Sand Hill, Oklahoma is 678 mi or 1091 km . It takes 10 hr 5 min to reach Sand Hill from Faribault by road. The distance by air route is 607 mi / 977 km.

There are 2 routes to reach Sand Hill, Oklahoma from Faribault, Minnesota.

Via I-35 S
678 mi / 1091 km - 10 hr 5 min
Via I-35 S and US-69 S
664 mi / 1069 km - 10 hr 12 min

Faribault, Minnesota

Time 18:26:30
Latitude 44.2949636
Longitude -93.268827
State Minnesota
Zip 55021
Timezone America/Menominee

Sand Hill, Oklahoma

Time 19:26:30
Latitude 35.6398372
Longitude -95.1953554
State Oklahoma
Zip
Timezone America/Indiana/Vincennes

Nearby Cities

North Oaks

64 mi / 103 km

Lake Summerset

312 mi / 502 km

Rock Island Arsenal

316 mi / 509 km

Argyle

318 mi / 512 km

Candlewick Lake

322 mi / 518 km

Timberlane

324 mi / 521 km

Capron

329 mi / 529 km

Offutt AFB

335 mi / 539 km

Niota

339 mi / 546 km

Union

351 mi / 565 km

Faribault Distance to Popular Cities

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