Distance from Faribault, Minnesota to Seymour, Indiana

Wondering how far is Seymour, Indiana from Faribault, Minnesota? Here's our driving distance calculation from Faribault to Seymour.

Distance
646 mi
1040 km
Travel Time
9 hr 36 min

The driving distance between Faribault, Minnesota and Seymour, Indiana is 646 mi or 1040 km . It takes 9 hr 36 min to reach Seymour from Faribault by road. The distance by air route is 530 mi / 853 km.

There are 3 routes to reach Seymour, Indiana from Faribault, Minnesota.

Via I-90 E and I-65 S
646 mi / 1040 km - 9 hr 36 min
Via I-90 E, I-294 S and I-65 S
653 mi / 1051 km - 9 hr 49 min
Via I-74
678 mi / 1091 km - 10 hr 5 min

Faribault, Minnesota

Time 13:15:58
Latitude 44.2949636
Longitude -93.268827
State Minnesota
Zip 55021
Timezone America/Menominee

Seymour, Indiana

Time 14:15:58
Latitude 38.9592201
Longitude -85.8902547
State Indiana
Zip 47274
Timezone America/Indiana/Vevay

Nearby Cities

North Oaks

64 mi / 103 km

Lake Summerset

312 mi / 502 km

Rock Island Arsenal

316 mi / 509 km

Argyle

318 mi / 512 km

Candlewick Lake

322 mi / 518 km

Timberlane

324 mi / 521 km

Capron

329 mi / 529 km

Offutt AFB

335 mi / 539 km

Niota

339 mi / 546 km

Union

351 mi / 565 km

Faribault Distance to Popular Cities

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