Distance from Inver Grove Heights, Minnesota to Sand Hill, Oklahoma

Wondering how far is Sand Hill, Oklahoma from Inver Grove Heights, Minnesota? Here's our driving distance calculation from Inver Grove Heights to Sand Hill.

Distance
726 mi
1168 km
Travel Time
10 hr 46 min

The driving distance between Inver Grove Heights, Minnesota and Sand Hill, Oklahoma is 726 mi or 1168 km . It takes 10 hr 46 min to reach Sand Hill from Inver Grove Heights by road. The distance by air route is 646 mi / 1040 km.

There are 2 routes to reach Sand Hill, Oklahoma from Inver Grove Heights, Minnesota.

Via I-35 S
726 mi / 1168 km - 10 hr 46 min
Via I-35 and I-35 S
870 mi / 1400 km - 12 hr 32 min

Inver Grove Heights, Minnesota

Time 10:03:46
Latitude 44.8480218
Longitude -93.0427153
State Minnesota
Zip
Timezone America/Menominee

Sand Hill, Oklahoma

Time 11:03:46
Latitude 35.6398372
Longitude -95.1953554
State Oklahoma
Zip
Timezone America/Indiana/Vincennes

Nearby Cities

North Oaks

20 mi / 32 km

Covington

331 mi / 533 km

Lake Summerset

312 mi / 502 km

Rock Island Arsenal

325 mi / 523 km

Baraga

351 mi / 565 km

Trimountain

353 mi / 568 km

Argyle

318 mi / 512 km

South Range

355 mi / 571 km

Caledonia

320 mi / 515 km

Atlantic Mine

357 mi / 575 km

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