Distance from Logan, Kansas to Sayreville, New Jersey
Wondering how far is Sayreville, New Jersey from Logan, Kansas? Here's our driving distance calculation from Logan to Sayreville.
The driving distance between Logan, Kansas and Sayreville, New Jersey is 1466 mi or 2359 km . It takes 22 hr 19 min to reach Sayreville from Logan by road. The distance by air route is 1330 mi / 2140 km.
There are 3 routes to reach Sayreville, New Jersey from Logan, Kansas.
1466 mi / 2359 km - 22 hr 19 min
1506 mi / 2424 km - 22 hr 27 min
1471 mi / 2367 km - 22 hr 20 min
Logan, Kansas
| Time | 12:04:00 |
| Latitude | 39.6616746 |
| Longitude | -99.5703854 |
| State | Kansas |
| Zip | 67646 |
| Timezone | America/Denver |
Sayreville, New Jersey
| Time | 14:04:00 |
| Latitude | 40.4594021 |
| Longitude | -74.360846 |
| State | New Jersey |
| Zip | |
| Timezone | America/New_York |
Logan Distance to Popular Cities
| Route | Distance |
|---|---|
| Logan to Edson | 116 mi / 187 km |
| Logan to Goodland | 125 mi / 201 km |
| Logan to Wauneta | 134 mi / 216 km |
| Logan to Max | 135 mi / 217 km |
| Logan to Wallace | 140 mi / 225 km |
| Logan to Kanorado | 142 mi / 229 km |
| Logan to Enders | 144 mi / 232 km |
| Logan to Parks | 147 mi / 237 km |
| Logan to Sharon Springs | 148 mi / 238 km |
| Logan to Imperial | 152 mi / 245 km |
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