Distance from Lyndon, Kansas to Seagoville, Texas

Wondering how far is Seagoville, Texas from Lyndon, Kansas? Here's our driving distance calculation from Lyndon to Seagoville.

Distance
502 mi
808 km
Travel Time
7 hr 15 min

The driving distance between Lyndon, Kansas and Seagoville, Texas is 502 mi or 808 km . It takes 7 hr 15 min to reach Seagoville from Lyndon by road. The distance by air route is 415 mi / 668 km.

There are 2 routes to reach Seagoville, Texas from Lyndon, Kansas.

Via I-35 S
502 mi / 808 km - 7 hr 15 min
Via US-75 S and US-75 S
460 mi / 740 km - 7 hr 29 min

Lyndon, Kansas

Time 23:10:36
Latitude 38.6100099
Longitude -95.684429
State Kansas
Zip 66451
Timezone America/Indiana/Vincennes

Seagoville, Texas

Time 23:10:36
Latitude 32.6395776
Longitude -96.5383228
State Texas
Zip 75159
Timezone America/Indiana/Vincennes

Nearby Cities

Ozawkie

54 mi / 87 km

Williamstown

54 mi / 87 km

Valley Falls

60 mi / 97 km

Oskaloosa

63 mi / 101 km

Nortonville

69 mi / 111 km

Winchester

71 mi / 114 km

Lake Quivira

74 mi / 119 km

Easton

80 mi / 129 km

Atchison

85 mi / 137 km

Lewis and Clark Village

91 mi / 146 km

Lyndon Distance to Popular Cities

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