Distance from Lyndon, Kansas to Stinesville, Indiana

Wondering how far is Stinesville, Indiana from Lyndon, Kansas? Here's our driving distance calculation from Lyndon to Stinesville.

Distance
534 mi
859 km
Travel Time
8 hr 6 min

The driving distance between Lyndon, Kansas and Stinesville, Indiana is 534 mi or 859 km . It takes 8 hr 6 min to reach Stinesville from Lyndon by road. The distance by air route is 487 mi / 784 km.

There are 3 routes to reach Stinesville, Indiana from Lyndon, Kansas.

Via I-70 E
534 mi / 859 km - 8 hr 6 min
Via I-70 E and I-64 E
595 mi / 958 km - 8 hr 50 min
Via US-36 E/Chicago - Kansas City Expy
575 mi / 925 km - 9 hr 14 min

Lyndon, Kansas

Time 23:20:51
Latitude 38.6100099
Longitude -95.684429
State Kansas
Zip 66451
Timezone America/Indiana/Vincennes

Stinesville, Indiana

Time 23:20:51
Latitude 39.2986569
Longitude -86.6522243
State Indiana
Zip
Timezone America/Indiana/Indianapolis

Nearby Cities

Ozawkie

54 mi / 87 km

Williamstown

54 mi / 87 km

Valley Falls

60 mi / 97 km

Oskaloosa

63 mi / 101 km

Nortonville

69 mi / 111 km

Winchester

71 mi / 114 km

Lake Quivira

74 mi / 119 km

Easton

80 mi / 129 km

Atchison

85 mi / 137 km

Lewis and Clark Village

91 mi / 146 km

Lyndon Distance to Popular Cities

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