Distance from Meadows Place, Texas to Jacksonville, North Carolina

Wondering how far is Jacksonville, North Carolina from Meadows Place, Texas? Here's our driving distance calculation from Meadows Place to Jacksonville.

Distance
1270 mi
2044 km
Travel Time
18 hr 28 min

The driving distance between Meadows Place, Texas and Jacksonville, North Carolina is 1270 mi or 2044 km . It takes 18 hr 28 min to reach Jacksonville from Meadows Place by road. The distance by air route is 1117 mi / 1798 km.

There are 3 routes to reach Jacksonville, North Carolina from Meadows Place, Texas.

Via I-10 E
1270 mi / 2044 km - 18 hr 28 min
Via I-20 E
1294 mi / 2082 km - 18 hr 53 min
Via I-10 E and I-85 N
1307 mi / 2103 km - 19 hr 26 min

Meadows Place, Texas

Time 09:41:05
Latitude 29.6513643
Longitude -95.5880883
State Texas
Zip
Timezone America/Indiana/Tell_City

Jacksonville, North Carolina

Time 10:41:05
Latitude 34.7540524
Longitude -77.4302414
State North Carolina
Zip
Timezone America/Kentucky/Monticello

Nearby Cities

Piney Point Village

12 mi / 19 km

Hedwig Village

14 mi / 23 km

Fresno

16 mi / 26 km

Brookside Village

20 mi / 32 km

Cinco Ranch

21 mi / 34 km

Pearland

23 mi / 37 km

Katy

28 mi / 45 km

Fulshear

28 mi / 45 km

Brookshire

35 mi / 56 km

Hillcrest

36 mi / 58 km

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