Distance from Parkersburg, Iowa to Boynton Beach, Florida

Wondering how far is Boynton Beach, Florida from Parkersburg, Iowa? Here's our driving distance calculation from Parkersburg to Boynton Beach.

Distance
1528 mi
2459 km
Travel Time
22 hr 31 min

The driving distance between Parkersburg, Iowa and Boynton Beach, Florida is 1528 mi or 2459 km . It takes 22 hr 31 min to reach Boynton Beach from Parkersburg by road. The distance by air route is 1320 mi / 2124 km.

There are 3 routes to reach Boynton Beach, Florida from Parkersburg, Iowa.

Via I-75 S
1528 mi / 2459 km - 22 hr 31 min
Via I-65 S and I-75 S
1612 mi / 2594 km - 23 hr 25 min
Via I-24 E and I-75 S
1546 mi / 2488 km - 23 hr 36 min

Parkersburg, Iowa

Time 13:26:32
Latitude 42.5774797
Longitude -92.7868634
State Iowa
Zip 50665
Timezone America/Chicago

Boynton Beach, Florida

Time 14:26:33
Latitude 26.5317866
Longitude -80.0905465
State Florida
Zip
Timezone America/Kentucky/Monticello

Nearby Cities

Rock Island Arsenal

171 mi / 275 km

North Oaks

212 mi / 341 km

Lake Summerset

192 mi / 309 km

Niota

193 mi / 311 km

Nauvoo

202 mi / 325 km

Ferris

209 mi / 336 km

Argyle

232 mi / 373 km

Timberlane

233 mi / 375 km

Caledonia

234 mi / 377 km

Candlewick Lake

236 mi / 380 km

Parkersburg Distance to Popular Cities

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