Distance from Parkland, Florida to Sawyer, Oklahoma

Wondering how far is Sawyer, Oklahoma from Parkland, Florida? Here's our driving distance calculation from Parkland to Sawyer.

Distance
1270 mi
2044 km
Travel Time
18 hr 34 min

The driving distance between Parkland, Florida and Sawyer, Oklahoma is 1270 mi or 2044 km . It takes 18 hr 34 min to reach Sawyer from Parkland by road. The distance by air route is 1046 mi / 1683 km.

There are 3 routes to reach Sawyer, Oklahoma from Parkland, Florida.

Via I-10 W
1270 mi / 2044 km - 18 hr 34 min
Via Florida's Tpke and I-10 W
1272 mi / 2047 km - 18 hr 35 min
Via I-10 W and I-49 N
1317 mi / 2120 km - 18 hr 44 min

Parkland, Florida

Time 04:17:13
Latitude 26.3107774
Longitude -80.2532249
State Florida
Zip
Timezone America/Kentucky/Monticello

Sawyer, Oklahoma

Time 04:17:13
Latitude 34.0137164
Longitude -95.3716238
State Oklahoma
Zip 74756
Timezone America/Indiana/Vincennes

Nearby Cities

Coconut Creek

9 mi / 14 km

Lauderdale Lakes

17 mi / 27 km

Lauderhill

19 mi / 31 km

Cooper City

25 mi / 40 km

West Park

30 mi / 48 km

Miramar

30 mi / 48 km

Palm Springs North

32 mi / 51 km

Wellington

37 mi / 60 km

Country Club

34 mi / 55 km

Royal Palm Estates

35 mi / 56 km

Parkland Distance to Popular Cities

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