Distance from San Fernando, California to Sebastopol, California

Wondering how far is Sebastopol, California from San Fernando, California? Here's our driving distance calculation from San Fernando to Sebastopol.

Distance
410 mi
660 km
Travel Time
6 hr 18 min

The driving distance between San Fernando, California and Sebastopol, California is 410 mi or 660 km . It takes 6 hr 18 min to reach Sebastopol from San Fernando by road. The distance by air route is 375 mi / 604 km.

There are 3 routes to reach Sebastopol, California from San Fernando, California.

Via I-5 N
410 mi / 660 km - 6 hr 18 min
Via I-5 N and US-101 N
441 mi / 710 km - 6 hr 55 min
Via US-101 N
466 mi / 750 km - 7 hr 19 min

San Fernando, California

Time 03:02:33
Latitude 34.2819461
Longitude -118.4389719
State California
Zip
Timezone America/Los_Angeles

Sebastopol, California

Time 03:02:33
Latitude 38.4021359
Longitude -122.8238806
State California
Zip 95472
Timezone America/Los_Angeles

Nearby Cities

Hidden Hills

23 mi / 37 km

Westlake Village

40 mi / 64 km

Rolling Hills

44 mi / 71 km

Rancho Santa Margarita

74 mi / 119 km

Edwards AFB

79 mi / 127 km

Trabuco Canyon

78 mi / 126 km

Coto De Caza

79 mi / 127 km

Lake Mathews

80 mi / 129 km

Canyon Lake

93 mi / 150 km

Camp Pendleton South

106 mi / 171 km

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