Distance from Savage, Maryland to Dixon, Oklahoma
Wondering how far is Dixon, Oklahoma from Savage, Maryland? Here's our driving distance calculation from Savage to Dixon.
The driving distance between Savage, Maryland and Dixon, Oklahoma is 1323 mi or 2129 km . It takes 19 hr 18 min to reach Dixon from Savage by road. The distance by air route is 1116 mi / 1796 km.
There are 2 routes to reach Dixon, Oklahoma from Savage, Maryland.
1323 mi / 2129 km - 19 hr 18 min
1293 mi / 2081 km - 19 hr 28 min
Savage, Maryland
Time | 17:00:07 |
Latitude | 39.144487 |
Longitude | -76.8317325 |
State | Maryland |
Zip | |
Timezone | America/New_York |
Dixon, Oklahoma
Time | 17:00:07 |
Latitude | 35.159523 |
Longitude | -96.5216797 |
State | Oklahoma |
Zip | 74884 |
Timezone | America/Indiana/Vincennes |
Nearby Cities
South Laurel
7 mi / 11 km
Konterra
8 mi / 13 km
White Oak
16 mi / 26 km
Layhill
18 mi / 29 km
Aspen Hill
20 mi / 32 km
Dundalk
24 mi / 39 km
Rockville
25 mi / 40 km
Rosedale
26 mi / 42 km
Derwood
27 mi / 43 km
Essex
27 mi / 43 km
Savage Distance to Popular Cities
Route | Distance |
---|---|
Savage to South Laurel | 7 mi / 11 km |
Savage to Konterra | 8 mi / 13 km |
Savage to White Oak | 16 mi / 26 km |
Savage to Layhill | 18 mi / 29 km |
Savage to Aspen Hill | 20 mi / 32 km |
Savage to Dundalk | 24 mi / 39 km |
Savage to Rockville | 25 mi / 40 km |
Savage to Rosedale | 26 mi / 42 km |
Savage to Derwood | 27 mi / 43 km |
Savage to Essex | 27 mi / 43 km |
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