Distance from Savage, Maryland to Hartley, Texas
Wondering how far is Hartley, Texas from Savage, Maryland? Here's our driving distance calculation from Savage to Hartley.
The driving distance between Savage, Maryland and Hartley, Texas is 1613 mi or 2596 km . It takes 24 hr to reach Hartley from Savage by road. The distance by air route is 1414 mi / 2276 km.
There are 2 routes to reach Hartley, Texas from Savage, Maryland.
1613 mi / 2596 km - 24 hr
1622 mi / 2610 km - 24 hr
Savage, Maryland
Time | 16:41:38 |
Latitude | 39.144487 |
Longitude | -76.8317325 |
State | Maryland |
Zip | |
Timezone | America/New_York |
Hartley, Texas
Time | 14:41:38 |
Latitude | 35.8855926 |
Longitude | -102.3968605 |
State | Texas |
Zip | |
Timezone | America/Denver |
Nearby Cities
South Laurel
7 mi / 11 km
Konterra
8 mi / 13 km
White Oak
16 mi / 26 km
Layhill
18 mi / 29 km
Aspen Hill
20 mi / 32 km
Dundalk
24 mi / 39 km
Rockville
25 mi / 40 km
Rosedale
26 mi / 42 km
Derwood
27 mi / 43 km
Essex
27 mi / 43 km
Savage Distance to Popular Cities
Route | Distance |
---|---|
Savage to South Laurel | 7 mi / 11 km |
Savage to Konterra | 8 mi / 13 km |
Savage to White Oak | 16 mi / 26 km |
Savage to Layhill | 18 mi / 29 km |
Savage to Aspen Hill | 20 mi / 32 km |
Savage to Dundalk | 24 mi / 39 km |
Savage to Rockville | 25 mi / 40 km |
Savage to Rosedale | 26 mi / 42 km |
Savage to Derwood | 27 mi / 43 km |
Savage to Essex | 27 mi / 43 km |
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