Distance from Savage, Maryland to Newton, Iowa
Wondering how far is Newton, Iowa from Savage, Maryland? Here's our driving distance calculation from Savage to Newton.
The driving distance between Savage, Maryland and Newton, Iowa is 985 mi or 1585 km . It takes 14 hr 47 min to reach Newton from Savage by road. The distance by air route is 870 mi / 1400 km.
There are 2 routes to reach Newton, Iowa from Savage, Maryland.
985 mi / 1585 km - 14 hr 47 min
1016 mi / 1635 km - 15 hr 22 min
Savage, Maryland
Time | 14:51:53 |
Latitude | 39.144487 |
Longitude | -76.8317325 |
State | Maryland |
Zip | |
Timezone | America/New_York |
Newton, Iowa
Time | 13:51:53 |
Latitude | 41.7033177 |
Longitude | -93.0573533 |
State | Iowa |
Zip | 50208 |
Timezone | America/Chicago |
Nearby Cities
South Laurel
7 mi / 11 km
Konterra
8 mi / 13 km
White Oak
16 mi / 26 km
Layhill
18 mi / 29 km
Aspen Hill
20 mi / 32 km
Dundalk
24 mi / 39 km
Rockville
25 mi / 40 km
Rosedale
26 mi / 42 km
Derwood
27 mi / 43 km
Essex
27 mi / 43 km
Savage Distance to Popular Cities
Route | Distance |
---|---|
Savage to South Laurel | 7 mi / 11 km |
Savage to Konterra | 8 mi / 13 km |
Savage to White Oak | 16 mi / 26 km |
Savage to Layhill | 18 mi / 29 km |
Savage to Aspen Hill | 20 mi / 32 km |
Savage to Dundalk | 24 mi / 39 km |
Savage to Rockville | 25 mi / 40 km |
Savage to Rosedale | 26 mi / 42 km |
Savage to Derwood | 27 mi / 43 km |
Savage to Essex | 27 mi / 43 km |
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