Distance from Savage, Maryland to Windsor, California
Wondering how far is Windsor, California from Savage, Maryland? Here's our driving distance calculation from Savage to Windsor.
The driving distance between Savage, Maryland and Windsor, California is 2829 mi or 4553 km . It takes 41 hr to reach Windsor from Savage by road. The distance by air route is 2448 mi / 3940 km.
There are 2 routes to reach Windsor, California from Savage, Maryland.
2829 mi / 4553 km - 41 hr
2844 mi / 4577 km - 42 hr
Savage, Maryland
Time | 14:54:29 |
Latitude | 39.144487 |
Longitude | -76.8317325 |
State | Maryland |
Zip | |
Timezone | America/New_York |
Windsor, California
Time | 11:54:29 |
Latitude | 38.5471327 |
Longitude | -122.8163802 |
State | California |
Zip | |
Timezone | America/Los_Angeles |
Nearby Cities
South Laurel
7 mi / 11 km
Konterra
8 mi / 13 km
White Oak
16 mi / 26 km
Layhill
18 mi / 29 km
Aspen Hill
20 mi / 32 km
Dundalk
24 mi / 39 km
Rockville
25 mi / 40 km
Rosedale
26 mi / 42 km
Derwood
27 mi / 43 km
Essex
27 mi / 43 km
Savage Distance to Popular Cities
Route | Distance |
---|---|
Savage to South Laurel | 7 mi / 11 km |
Savage to Konterra | 8 mi / 13 km |
Savage to White Oak | 16 mi / 26 km |
Savage to Layhill | 18 mi / 29 km |
Savage to Aspen Hill | 20 mi / 32 km |
Savage to Dundalk | 24 mi / 39 km |
Savage to Rockville | 25 mi / 40 km |
Savage to Rosedale | 26 mi / 42 km |
Savage to Derwood | 27 mi / 43 km |
Savage to Essex | 27 mi / 43 km |
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