Distance from Seaford, New York to Jacksonville, Texas

Wondering how far is Jacksonville, Texas from Seaford, New York? Here's our driving distance calculation from Seaford to Jacksonville.

Distance
1558 mi
2507 km
Travel Time
23 hr 5 min

The driving distance between Seaford, New York and Jacksonville, Texas is 1558 mi or 2507 km . It takes 23 hr 5 min to reach Jacksonville from Seaford by road. The distance by air route is 1348 mi / 2169 km.

There are 3 routes to reach Jacksonville, Texas from Seaford, New York.

Via I-81 S
1558 mi / 2507 km - 23 hr 5 min
Via I-40 W
1557 mi / 2506 km - 23 hr 21 min
Via I-76 W
1593 mi / 2564 km - 24 hr

Seaford, New York

Time 00:28:59
Latitude 40.6659344
Longitude -73.4881809
State New York
Zip
Timezone America/New_York

Jacksonville, Texas

Time 23:28:59
Latitude 31.963778
Longitude -95.2705042
State Texas
Zip 75766
Timezone America/Indiana/Tell_City

Nearby Cities

East Atlantic Beach

19 mi / 31 km

Matinecock

21 mi / 34 km

Kings Point

25 mi / 40 km

Saltaire

25 mi / 40 km

Fire Island

29 mi / 47 km

Ocean Beach

28 mi / 45 km

Bronx

35 mi / 56 km

Fort Lee

37 mi / 60 km

New Rochelle

37 mi / 60 km

Leonia

38 mi / 61 km

Seaford Distance to Popular Cities

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