Distance from Seaford, New York to North Puyallup, Washington

Wondering how far is North Puyallup, Washington from Seaford, New York? Here's our driving distance calculation from Seaford to North Puyallup.

Distance
2900 mi
4667 km
Travel Time
42 hr

The driving distance between Seaford, New York and North Puyallup, Washington is 2900 mi or 4667 km . It takes 42 hr to reach North Puyallup from Seaford by road. The distance by air route is 2428 mi / 3907 km.

There are 2 routes to reach North Puyallup, Washington from Seaford, New York.

Via I-80 W, I-94 W and I-90 W
2900 mi / 4667 km - 42 hr
Via I-80 W, I-94 W and I-90 W
2856 mi / 4596 km - 43 hr

Seaford, New York

Time 06:56:33
Latitude 40.6659344
Longitude -73.4881809
State New York
Zip
Timezone America/New_York

North Puyallup, Washington

Time 04:56:33
Latitude 47.2067673
Longitude -122.282342
State Washington
Zip 98372
Timezone America/Boise

Nearby Cities

East Atlantic Beach

19 mi / 31 km

Matinecock

21 mi / 34 km

Kings Point

25 mi / 40 km

Saltaire

25 mi / 40 km

Fire Island

29 mi / 47 km

Ocean Beach

28 mi / 45 km

Bronx

35 mi / 56 km

Fort Lee

37 mi / 60 km

New Rochelle

37 mi / 60 km

Leonia

38 mi / 61 km

Seaford Distance to Popular Cities

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