Distance from Seneca, Illinois to Jefferson, Ohio
Wondering how far is Jefferson, Ohio from Seneca, Illinois? Here's our driving distance calculation from Seneca to Jefferson.
The driving distance between Seneca, Illinois and Jefferson, Ohio is 446 mi or 718 km . It takes 6 hr 51 min to reach Jefferson from Seneca by road. The distance by air route is 406 mi / 653 km.
There are 3 routes to reach Jefferson, Ohio from Seneca, Illinois.
446 mi / 718 km - 6 hr 51 min
446 mi / 718 km - 6 hr 50 min
565 mi / 909 km - 8 hr 48 min
Seneca, Illinois
Time | 06:02:06 |
Latitude | 41.3111442 |
Longitude | -88.6097936 |
State | Illinois |
Zip | |
Timezone | America/Chicago |
Jefferson, Ohio
Time | 07:02:06 |
Latitude | 41.7386662 |
Longitude | -80.7698066 |
State | Ohio |
Zip | 44047 |
Timezone | America/Detroit |
Nearby Cities
Homer Glen
50 mi / 80 km
Homewood
59 mi / 95 km
East Hazel Crest
59 mi / 95 km
Posen
59 mi / 95 km
Dixmoor
60 mi / 97 km
Harvey
60 mi / 97 km
Riverdale
61 mi / 98 km
Phoenix
62 mi / 100 km
Thornton
62 mi / 100 km
La Grange Park
63 mi / 101 km
Seneca Distance to Popular Cities
Route | Distance |
---|---|
Seneca to Homer Glen | 50 mi / 80 km |
Seneca to Homewood | 59 mi / 95 km |
Seneca to East Hazel Crest | 59 mi / 95 km |
Seneca to Posen | 59 mi / 95 km |
Seneca to Dixmoor | 60 mi / 97 km |
Seneca to Harvey | 60 mi / 97 km |
Seneca to Riverdale | 61 mi / 98 km |
Seneca to Phoenix | 62 mi / 100 km |
Seneca to Thornton | 62 mi / 100 km |
Seneca to La Grange Park | 63 mi / 101 km |
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