Distance from Shenandoah Junction, West Virginia to Alexander, Kansas

Wondering how far is Alexander, Kansas from Shenandoah Junction, West Virginia? Here's our driving distance calculation from Shenandoah Junction to Alexander.

Distance
1309 mi
2107 km
Travel Time
19 hr 45 min

The driving distance between Shenandoah Junction, West Virginia and Alexander, Kansas is 1309 mi or 2107 km . It takes 19 hr 45 min to reach Alexander from Shenandoah Junction by road. The distance by air route is 1166 mi / 1876 km.

There are 3 routes to reach Alexander, Kansas from Shenandoah Junction, West Virginia.

Via I-70 W
1309 mi / 2107 km - 19 hr 45 min
Via I-72 W and I-70 W
1343 mi / 2161 km - 20 hr 21 min
Via I-64 W and I-70 W
1363 mi / 2194 km - 20 hr 16 min

Shenandoah Junction, West Virginia

Time 13:06:40
Latitude 39.3587115
Longitude -77.8430506
State West Virginia
Zip 25442
Timezone America/New_York

Alexander, Kansas

Time 11:06:40
Latitude 38.4694588
Longitude -99.5531697
State Kansas
Zip 67513
Timezone America/Denver

Nearby Cities

Wilson-Conococheague

35 mi / 56 km

Brambleton

39 mi / 63 km

Arcola

41 mi / 66 km

McNair

45 mi / 72 km

Herndon

45 mi / 72 km

Reston

47 mi / 76 km

South Riding

48 mi / 77 km

Chantilly

48 mi / 77 km

Navy

52 mi / 84 km

Difficult Run

53 mi / 85 km

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