Distance from Shenandoah Junction, West Virginia to Sioux Center, Iowa

Wondering how far is Sioux Center, Iowa from Shenandoah Junction, West Virginia? Here's our driving distance calculation from Shenandoah Junction to Sioux Center.

Distance
1178 mi
1896 km
Travel Time
17 hr 55 min

The driving distance between Shenandoah Junction, West Virginia and Sioux Center, Iowa is 1178 mi or 1896 km . It takes 17 hr 55 min to reach Sioux Center from Shenandoah Junction by road. The distance by air route is 985 mi / 1585 km.

There are 2 routes to reach Sioux Center, Iowa from Shenandoah Junction, West Virginia.

Via I-80 W
1178 mi / 1896 km - 17 hr 55 min
Via I-70 W
1210 mi / 1947 km - 18 hr 29 min

Shenandoah Junction, West Virginia

Time 13:19:42
Latitude 39.3587115
Longitude -77.8430506
State West Virginia
Zip 25442
Timezone America/New_York

Sioux Center, Iowa

Time 12:19:42
Latitude 43.0797991
Longitude -96.1756935
State Iowa
Zip 51250
Timezone America/North_Dakota/New_Salem

Nearby Cities

Wilson-Conococheague

35 mi / 56 km

Brambleton

39 mi / 63 km

Arcola

41 mi / 66 km

McNair

45 mi / 72 km

Herndon

45 mi / 72 km

Reston

47 mi / 76 km

South Riding

48 mi / 77 km

Chantilly

48 mi / 77 km

Navy

52 mi / 84 km

Difficult Run

53 mi / 85 km

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