Distance from Shueyville, Iowa to Boynton Beach, Florida

Wondering how far is Boynton Beach, Florida from Shueyville, Iowa? Here's our driving distance calculation from Shueyville to Boynton Beach.

Distance
1437 mi
2313 km
Travel Time
20 hr 50 min

The driving distance between Shueyville, Iowa and Boynton Beach, Florida is 1437 mi or 2313 km . It takes 20 hr 50 min to reach Boynton Beach from Shueyville by road. The distance by air route is 1245 mi / 2004 km.

There are 3 routes to reach Boynton Beach, Florida from Shueyville, Iowa.

Via I-75 S
1437 mi / 2313 km - 20 hr 50 min
Via I-24 E and I-75 S
1467 mi / 2361 km - 21 hr 13 min
Via I-74 and I-75 S
1558 mi / 2507 km - 22 hr 18 min

Shueyville, Iowa

Time 03:50:39
Latitude 41.8476768
Longitude -91.6461094
State Iowa
Zip
Timezone America/Chicago

Boynton Beach, Florida

Time 04:50:39
Latitude 26.5317866
Longitude -80.0905465
State Florida
Zip
Timezone America/Kentucky/Monticello

Nearby Cities

Rock Island Arsenal

79 mi / 127 km

Lake Summerset

151 mi / 243 km

Belvidere

197 mi / 317 km

Argyle

198 mi / 319 km

Timberlane

199 mi / 320 km

Caledonia

200 mi / 322 km

Garden Prairie

202 mi / 325 km

Candlewick Lake

202 mi / 325 km

Poplar Grove

204 mi / 328 km

Marengo

208 mi / 335 km

Shueyville Distance to Popular Cities

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