Distance from Shueyville, Iowa to Norton, Virginia

Wondering how far is Norton, Virginia from Shueyville, Iowa? Here's our driving distance calculation from Shueyville to Norton.

Distance
739 mi
1189 km
Travel Time
11 hr 12 min

The driving distance between Shueyville, Iowa and Norton, Virginia is 739 mi or 1189 km . It takes 11 hr 12 min to reach Norton from Shueyville by road. The distance by air route is 589 mi / 948 km.

There are 3 routes to reach Norton, Virginia from Shueyville, Iowa.

Via I-74
739 mi / 1189 km - 11 hr 12 min
Via I-64 E
782 mi / 1259 km - 12 hr 3 min
Via I-80 E and I-65 S
762 mi / 1226 km - 11 hr 39 min

Shueyville, Iowa

Time 08:07:19
Latitude 41.8476768
Longitude -91.6461094
State Iowa
Zip
Timezone America/Chicago

Norton, Virginia

Time 09:07:19
Latitude 36.933433
Longitude -82.6290459
State Virginia
Zip 24273
Timezone America/Kentucky/Monticello

Nearby Cities

Rock Island Arsenal

79 mi / 127 km

Lake Summerset

151 mi / 243 km

Belvidere

197 mi / 317 km

Argyle

198 mi / 319 km

Timberlane

199 mi / 320 km

Caledonia

200 mi / 322 km

Garden Prairie

202 mi / 325 km

Candlewick Lake

202 mi / 325 km

Poplar Grove

204 mi / 328 km

Marengo

208 mi / 335 km

Shueyville Distance to Popular Cities

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