Distance from Shueyville, Iowa to Severn, Maryland

Wondering how far is Severn, Maryland from Shueyville, Iowa? Here's our driving distance calculation from Shueyville to Severn.

Distance
926 mi
1490 km
Travel Time
13 hr 47 min

The driving distance between Shueyville, Iowa and Severn, Maryland is 926 mi or 1490 km . It takes 13 hr 47 min to reach Severn from Shueyville by road. The distance by air route is 806 mi / 1297 km.

There are 3 routes to reach Severn, Maryland from Shueyville, Iowa.

Via I-80 E
926 mi / 1490 km - 13 hr 47 min
Via I-74 and I-70 E
972 mi / 1564 km - 14 hr 23 min
Via I-80 E, I-74 and I-70 E
956 mi / 1539 km - 14 hr 20 min

Shueyville, Iowa

Time 03:48:47
Latitude 41.8476768
Longitude -91.6461094
State Iowa
Zip
Timezone America/Chicago

Severn, Maryland

Time 04:48:47
Latitude 39.1370528
Longitude -76.6983022
State Maryland
Zip
Timezone America/New_York

Nearby Cities

Rock Island Arsenal

79 mi / 127 km

Lake Summerset

151 mi / 243 km

Belvidere

197 mi / 317 km

Argyle

198 mi / 319 km

Timberlane

199 mi / 320 km

Caledonia

200 mi / 322 km

Garden Prairie

202 mi / 325 km

Candlewick Lake

202 mi / 325 km

Poplar Grove

204 mi / 328 km

Marengo

208 mi / 335 km

Shueyville Distance to Popular Cities

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