Distance from Sissonville, West Virginia to Bowdon, North Dakota
Wondering how far is Bowdon, North Dakota from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Bowdon.
The driving distance between Sissonville, West Virginia and Bowdon, North Dakota is 1300 mi or 2092 km . It takes 19 hr 20 min to reach Bowdon from Sissonville by road. The distance by air route is 1098 mi / 1767 km.
There are 3 routes to reach Bowdon, North Dakota from Sissonville, West Virginia.
1300 mi / 2092 km - 19 hr 20 min
1276 mi / 2054 km - 19 hr 32 min
1371 mi / 2206 km - 20 hr 8 min
Sissonville, West Virginia
Time | 03:57:22 |
Latitude | 38.5281485 |
Longitude | -81.6309601 |
State | West Virginia |
Zip | |
Timezone | America/Indiana/Vevay |
Bowdon, North Dakota
Time | 02:57:22 |
Latitude | 47.4697217 |
Longitude | -99.7078981 |
State | North Dakota |
Zip | 58418 |
Timezone | America/North_Dakota/Center |
Sissonville Distance to Popular Cities
Route | Distance |
---|---|
Sissonville to Eskdale | 41 mi / 66 km |
Sissonville to Pax | 61 mi / 98 km |
Sissonville to Scarbro | 64 mi / 103 km |
Sissonville to Oak Hill | 65 mi / 105 km |
Sissonville to Hilltop | 66 mi / 106 km |
Sissonville to Glen Jean | 66 mi / 106 km |
Sissonville to Mt Hope | 68 mi / 109 km |
Sissonville to Prosperity | 71 mi / 114 km |
Sissonville to Bradley | 71 mi / 114 km |
Sissonville to Gatewood | 72 mi / 116 km |
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