Distance from Sissonville, West Virginia to Braddock, North Dakota
Wondering how far is Braddock, North Dakota from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Braddock.
The driving distance between Sissonville, West Virginia and Braddock, North Dakota is 1298 mi or 2089 km . It takes 19 hr 32 min to reach Braddock from Sissonville by road. The distance by air route is 1087 mi / 1749 km.
There are 2 routes to reach Braddock, North Dakota from Sissonville, West Virginia.
1298 mi / 2089 km - 19 hr 32 min
1274 mi / 2050 km - 19 hr 44 min
Sissonville, West Virginia
Time | 17:31:11 |
Latitude | 38.5281485 |
Longitude | -81.6309601 |
State | West Virginia |
Zip | |
Timezone | America/Indiana/Vevay |
Braddock, North Dakota
Time | 16:31:11 |
Latitude | 46.5644311 |
Longitude | -100.0909421 |
State | North Dakota |
Zip | 58524 |
Timezone | America/North_Dakota/New_Salem |
Sissonville Distance to Popular Cities
Route | Distance |
---|---|
Sissonville to Eskdale | 41 mi / 66 km |
Sissonville to Pax | 61 mi / 98 km |
Sissonville to Scarbro | 64 mi / 103 km |
Sissonville to Oak Hill | 65 mi / 105 km |
Sissonville to Hilltop | 66 mi / 106 km |
Sissonville to Glen Jean | 66 mi / 106 km |
Sissonville to Mt Hope | 68 mi / 109 km |
Sissonville to Prosperity | 71 mi / 114 km |
Sissonville to Bradley | 71 mi / 114 km |
Sissonville to Gatewood | 72 mi / 116 km |
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