Distance from Sissonville, West Virginia to Bucyrus, North Dakota
Wondering how far is Bucyrus, North Dakota from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Bucyrus.
The driving distance between Sissonville, West Virginia and Bucyrus, North Dakota is 1481 mi or 2383 km . It takes 21 hr 52 min to reach Bucyrus from Sissonville by road. The distance by air route is 1195 mi / 1923 km.
There are 3 routes to reach Bucyrus, North Dakota from Sissonville, West Virginia.
1481 mi / 2383 km - 21 hr 52 min
1457 mi / 2345 km - 22 hr 4 min
1569 mi / 2525 km - 22 hr 53 min
Sissonville, West Virginia
| Time | 17:24:13 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Bucyrus, North Dakota
| Time | 16:24:13 |
| Latitude | 46.0638952 |
| Longitude | -102.7882137 |
| State | North Dakota |
| Zip | 58639 |
| Timezone | America/North_Dakota/New_Salem |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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