Distance from Sissonville, West Virginia to Dutch Flat, California
Wondering how far is Dutch Flat, California from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Dutch Flat.
The driving distance between Sissonville, West Virginia and Dutch Flat, California is 2426 mi or 3904 km . It takes 35 hr to reach Dutch Flat from Sissonville by road. The distance by air route is 2093 mi / 3368 km.
There are 2 routes to reach Dutch Flat, California from Sissonville, West Virginia.
2426 mi / 3904 km - 35 hr
2416 mi / 3888 km - 36 hr
Sissonville, West Virginia
| Time | 09:51:16 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Dutch Flat, California
| Time | 06:51:16 |
| Latitude | 39.2059586 |
| Longitude | -120.8378103 |
| State | California |
| Zip | |
| Timezone | America/Los_Angeles |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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