Distance from Sissonville, West Virginia to Jamestown, North Dakota
Wondering how far is Jamestown, North Dakota from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Jamestown.
The driving distance between Sissonville, West Virginia and Jamestown, North Dakota is 1226 mi or 1973 km . It takes 18 hr 12 min to reach Jamestown from Sissonville by road. The distance by air route is 1039 mi / 1672 km.
There are 2 routes to reach Jamestown, North Dakota from Sissonville, West Virginia.
1226 mi / 1973 km - 18 hr 12 min
1202 mi / 1934 km - 18 hr 24 min
Sissonville, West Virginia
| Time | 15:29:27 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Jamestown, North Dakota
| Time | 14:29:27 |
| Latitude | 46.9105438 |
| Longitude | -98.7084357 |
| State | North Dakota |
| Zip | |
| Timezone | America/North_Dakota/Center |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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