Distance from Sissonville, West Virginia to Jefferson, Iowa
Wondering how far is Jefferson, Iowa from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Jefferson.
The driving distance between Sissonville, West Virginia and Jefferson, Iowa is 836 mi or 1345 km . It takes 12 hr 51 min to reach Jefferson from Sissonville by road. The distance by air route is 713 mi / 1147 km.
There are 3 routes to reach Jefferson, Iowa from Sissonville, West Virginia.
836 mi / 1345 km - 12 hr 51 min
840 mi / 1352 km - 12 hr 54 min
898 mi / 1445 km - 13 hr 24 min
Sissonville, West Virginia
| Time | 03:10:08 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Jefferson, Iowa
| Time | 02:10:08 |
| Latitude | 42.0172457 |
| Longitude | -94.3774232 |
| State | Iowa |
| Zip | 50129 |
| Timezone | America/Chicago |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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