Distance from Sissonville, West Virginia to Jefferson, South Dakota
Wondering how far is Jefferson, South Dakota from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Jefferson.
The driving distance between Sissonville, West Virginia and Jefferson, South Dakota is 976 mi or 1571 km . It takes 14 hr 54 min to reach Jefferson from Sissonville by road. The distance by air route is 831 mi / 1337 km.
There are 3 routes to reach Jefferson, South Dakota from Sissonville, West Virginia.
976 mi / 1571 km - 14 hr 54 min
992 mi / 1596 km - 14 hr 57 min
1055 mi / 1698 km - 15 hr 24 min
Sissonville, West Virginia
Time | 03:09:54 |
Latitude | 38.5281485 |
Longitude | -81.6309601 |
State | West Virginia |
Zip | |
Timezone | America/Indiana/Vevay |
Jefferson, South Dakota
Time | 02:09:54 |
Latitude | 42.6024951 |
Longitude | -96.5591992 |
State | South Dakota |
Zip | 57038 |
Timezone | America/North_Dakota/New_Salem |
Sissonville Distance to Popular Cities
Route | Distance |
---|---|
Sissonville to Eskdale | 41 mi / 66 km |
Sissonville to Pax | 61 mi / 98 km |
Sissonville to Scarbro | 64 mi / 103 km |
Sissonville to Oak Hill | 65 mi / 105 km |
Sissonville to Hilltop | 66 mi / 106 km |
Sissonville to Glen Jean | 66 mi / 106 km |
Sissonville to Mt Hope | 68 mi / 109 km |
Sissonville to Prosperity | 71 mi / 114 km |
Sissonville to Bradley | 71 mi / 114 km |
Sissonville to Gatewood | 72 mi / 116 km |
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